3x^2=10^10

Solution for 3x^2=10^10 equation:

3x^2=10^10

We move all terms to the left:

3x^2-(10^10)=0

We add all the numbers together, and all the variables

3x^2-10000000000=0

a = 3; b = 0; c = -10000000000;
Δ = b2-4ac
Δ = 02-4·3·(-10000000000)
Δ = 120000000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{120000000000}=\sqrt{40000000000*3}=\sqrt{40000000000}*\sqrt{3}=200000\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-200000\sqrt{3}}{2*3}=\frac{0-200000\sqrt{3}}{6}
=-\frac{200000\sqrt{3}}{6}
=-\frac{100000\sqrt{3}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+200000\sqrt{3}}{2*3}=\frac{0+200000\sqrt{3}}{6}
=\frac{200000\sqrt{3}}{6}
=\frac{100000\sqrt{3}}{3}
$